C++實現(xiàn)判斷一個區(qū)間內(nèi)的所有回文數(shù)，并輸出：

#include<iostream>
using namespace std;

int cirJudge(int n)
{
    int sum = 0, w = 1, h = 0;
    int m,flag = 0;
    m = n;
    while (n)
    {
        h = n % 10;
        sum = sum * w + h;
        n = n / 10;
        w = 10;
    }
    if (sum == m)
    {
        flag = 1;
    }
    return flag;
}
int main()
{
    int L,R;
    while (cin >> L >> R)
    {
        for (int i = L; i <= R; i++)
        {
            if (cirJudge(i))
            {
                cout << i << " ";
            }
        }
        cout << endl;
    }
    return 0;
}