一、

• 思路：將數(shù)值與索引綁定，遍歷相鄰元素即可
• 注意：可以用Arrays.sort或者TreeMap實(shí)現(xiàn)
• 代碼

import java.util.*;
// 注意類名必須為 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        for (int i  = 0; i < t; i++) {
            int n = in.nextInt();
            int[] val = new int[n];
            for (int j = 0; j < n; j++) {
                val[j] = in.nextInt();
            }
            Integer[] idx = new Integer[n];
            for (int j = 0; j < n; j++) {
                idx[j] = j;
            }
            Arrays.sort(idx, Comparator.comparingInt(k -> val[k]));
            int pos = 0, neg = 0;
            for (int j = 0; j < n - 1; j++) {
                if (idx[j + 1] > idx[j]) {
                    pos++;
                } else {
                    neg++;
                }
            }
            System.out.println(pos + " " + neg);
        }
    }
}