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給定一個二叉樹根節(jié)點，請你判斷這棵樹是不是二叉搜索樹。 二叉搜索樹滿足每個節(jié)點的左子樹上的所有節(jié)點均小于當(dāng)前節(jié)點且右子樹上的所有節(jié)點均大于當(dāng)前節(jié)點。 例： 圖1 圖2 數(shù)據(jù)范圍：節(jié)點數(shù)量滿足 ，節(jié)點上的值滿足
示例1
輸入
{1,2,3}
輸出
false
說明
如題面圖1
示例2
輸入
{2,1,3}
輸出
true
說明
如題面圖2
加載中...
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ public boolean isValidBST (TreeNode root) { // write code here } }
/** * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * }; */ class Solution { public: /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ bool isValidBST(TreeNode* root) { // write code here } };
#coding:utf-8 # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None # # 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 # # # @param root TreeNode類 # @return bool布爾型 # class Solution: def isValidBST(self , root ): # write code here
using System; using System.Collections.Generic; /* public class TreeNode { public int val; public TreeNode left; public TreeNode right; public TreeNode (int x) { val = x; } } */ class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ public bool isValidBST (TreeNode root) { // write code here } }
/* * function TreeNode(x) { * this.val = x; * this.left = null; * this.right = null; * } */ /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ function isValidBST( root ) { // write code here } module.exports = { isValidBST : isValidBST };
<?php /*class TreeNode{ var $val; var $left = NULL; var $right = NULL; function __construct($val){ $this->val = $val; } }*/ /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ function isValidBST( $root ) { // write code here }
# class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None # # 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 # # # @param root TreeNode類 # @return bool布爾型 # class Solution: def isValidBST(self , root: TreeNode) -> bool: # write code here
package main import "fmt" import . "nc_tools" /* * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ func isValidBST( root *TreeNode ) bool { // write code here }
/** * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * }; */ /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ bool isValidBST(struct TreeNode* root ) { // write code here }
# class TreeNode # attr_accessor :val, :left, :right # def initialize(val, left = nil, right = nil) # @val, @left, @right = val, left, right # end # end # # 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 # # # @param root TreeNode類 # @return bool布爾型 # class Solution def isValidBST(root) # write code here end end
/** * class TreeNode(var val: Int) { * var left: TreeNode = null * var right: TreeNode = null * } */ object Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ def isValidBST(root: TreeNode): Boolean = { // write code here } }
/** * class TreeNode(var `val`: Int) { * var left: TreeNode? = null * var right: TreeNode? = null * } */ object Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ fun isValidBST(root: TreeNode?): Boolean { // write code here } }
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ public boolean isValidBST (TreeNode root) { // write code here } }
/*class TreeNode { * val: number * left: TreeNode | null * right: TreeNode | null * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) { * this.val = (val===undefined ? 0 : val) * this.left = (left===undefined ? null : left) * this.right = (right===undefined ? null : right) * } * } */ /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ export function isValidBST(root: TreeNode): boolean { // write code here }
/** * public class TreeNode { * public var val: Int * public var left: TreeNode? * public var right: TreeNode? * public init(_ val: Int=0, _ left: TreeNode?=nil, _ right: TreeNode?=nil) { * self.val = val * self.left = left * self.right = right * } */ public class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ func isValidBST ( _ root: TreeNode?) -> Bool { // write code here } }
/** * #[derive(PartialEq, Eq, Debug, Clone)] * pub struct TreeNode { * pub val: i32, * pub left: Option<Box<TreeNode>>, * pub right: Option<Box<TreeNode>>, * } * * impl TreeNode { * #[inline] * fn new(val: i32) -> Self { * TreeNode { * val: val, * left: None, * right: None, * } * } * } */ struct Solution{ } impl Solution { fn new() -> Self { Solution{} } /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請勿修改，直接返回方法規(guī)定的值即可 * * * @param root TreeNode類 * @return bool布爾型 */ pub fn isValidBST(&self, root: Option<Box<TreeNode>>) -> bool { // write code here } }
{1,2,3}
false
{2,1,3}
true